Question

divide (-x^6+2x^2+4x^3+2x^2) by (2√2x^2)​

Answer 1

Step-by-step explanation:

$\frac{-x^6+2x^2+4x^3+2x^2}{2√2x^2} \\ = \frac{ -x {}^{6}}{2√2x^2} + \frac{4x {}^{3} }{2√2x^2} + \frac{4x {}^{2} }{2√2x^2} \\ = - \frac{x {}^{4} }{2 \sqrt{2} } + \sqrt{2}x + \sqrt{2}$