Question

divide (x) by g(x) in p(x)=2x4+3x2--2x2-9x-12 by g(x)=x2-3​

Answer 1

Answer:

$\frac{2x^4+3x^2-2x^2-9x-12}{x^2-3}\\= \frac{2x^4+x^2-9x-12}{x^2-3}\\= 2x^2+\frac{7x^2-9x-12}{x^2-3}\\= 2x^2+7+\frac{-9x+9}{x^2-3}$

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