divide x cube + 3 X square + 3 X + 1 by X + 1 find the remainder
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Answered by
3
hey
The remainder will be 0
as x-1 is a factor of x^3 + 3x^2 + 3x + 1
The remainder will be 0
as x-1 is a factor of x^3 + 3x^2 + 3x + 1
Answered by
9
x³ + 3x² + 3x + 1 = p(x)
x + 1 = Divisor
By Remainder Theorem :
x + 1 = 0
x = (-1)
p(x) = x³ + 3x² + 3x + 1
p(-1) = (-1)³ + 3(-1)² + 3(-1) + 1
p(-1) = -1 + 3 - 3 + 1
p(-1) = 0
Hence Remainder = 0
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