divide -x²+6x³-3-10xby (2x-3) find the quotient and remainder also check your answer
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Step-by-step explanation:
let 2x-3=0
x=3/2
f(x)=6x³-x²-10x-3
f(3/2)=6(27/8)-(9/4)-10(3/2)-3
R=81-9-60-12/4
R=0/4
R=0
using long division method find the quotient
f(x)=(2x-3)(3x^2+4x+1)
=(2x-3)(3x^2+3x+x+1)
=(2x-3)[3x(x+1)+1(x+1)]
=(2x-3)(x+1)(3x+1)
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