Question

divide (x³+ 1) by (x-l)


pls jldi bta do​

Answer 1

Answer:

=$\frac{ {x}^{3 } + 1}{x - 1}$

=$\frac{ {x}^{3} + {1}^{3} }{x - 1}$

=$\frac{(x - 1)( {x}^{2} + xy + {1}^{2}) }{(x - 1)}$

=${x}^{2} + xy + 1$

Answer 2

Explanation:

Q) (x³+ 1) by (x-1)

Ans:-

$( {x}^{3} + 1) = (x - 1)( {x}^{2} + x + 1)$

now:

by dividing, we get:

$( {x}^{2} + x + 1)$

hope it helps :)