Divide x³-3x²+5x-3 by [x²-2] and find quotient
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Answered by
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Answer: the answer is remainder 12
Step-by-step explanation:
the numerator
consider the numerator
x
3
(
x
−
2
)
+
2
x
3
−
3
x
2
+
7
x
+
3
=
x
3
(
x
−
2
)
+
2
x
2
(
x
−
2
)
+
4
x
2
−
3
x
2
+
7
x
+
3
=
x
3
(
x
−
2
)
+
2
x
2
(
x
−
2
)
+
x
(
x
−
2
)
+
2
x
+
7
x
+
3
=
x
3
(
x
−
2
)
+
2
x
2
(
x
−
2
)
+
x
(
x
−
2
)
+
9
(
x
−
2
)
+
18
+
3
=
x
3
(
x
−
2
)
+
2
x
2
(
x
−
2
)
+
x
(
x
−
2
)
+
9
(
x
−
2
)
+
21
quotient
=
x
3
+
2
x
2
+
x
+
9
,
remainder
=
21
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