Divide x³–3x²y+3xy²–y³ by x–y
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Answered by
14
Answer:
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Step-by-step explanation:
=x3-3x^3y+3xy^2-y^3/x-y
=(x-y)^3/(x-y)
=(x-y)^2
=x^2+y^2-2xy
Answered by
2
Answer:
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Step-by-step explanation:
=x3-3x^3y+3xy^2-y^3/x-y
=(x-y)^3/(x-y)
=(x-y)^2
=x^2+y^2-2xy
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