Question

Divide (x³- 3x²y+3xy²- y³) by ( x-y )
By long division method. ​

Answer 1

(x³- 3x²y+3xy²- y³) / ( x-y )

= (x-y)³ / (x-y) [ x³- 3x²y+3xy²- y³ = (x-y)³ ]

= (x-y)² = x² + y² - 2xy

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Answer 2

Answer:

= (x-y)² = x² + y² - 2xy

Step-by-step explanation: