Question

Divide y ^3 + y ^2 - 2y + 1 by y - a

Answer 1

Step-by-step explanation:

\begin{lstlisting}[language=Python, caption=Python example]

import numpy as np

def incmatrix(genl1,genl2):

m = len(genl1)

n = len(genl2)

M = None #to become the incidence matrix

VT = np.zeros((n*m,1), int) #dummy variable

#compute the bitwise xor matrix

M1 = bitxormatrix(genl1)

M2 = np.triu(bitxormatrix(genl2),1)

for i in range(m-1):

for j in range(i+1, m):

[r,c] = np.where(M2 == M1[i,j])

for k in range(len(r)):

VT[(i)*n + r[k]] = 1;

VT[(i)*n + c[k]] = 1;

VT[(j)*n + r[k]] = 1;

VT[(j)*n + c[k]] = 1;

if M is None:

M = np.copy(VT)

else:

M = np.concatenate((M, VT), 1)

VT = np.zeros((n*m,1), int)

return M

\end{lstlisting}

Answer 2

Hope this will help u dude♠☝