Question

divide: (y^4 -81) by (y-3)​

Answer 1

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$\frac{ {y}^{4} - 81 }{y - 3} \\ \\ = > \frac{ {y}^{4} - {3}^{4} }{y - 3} \\ \\ = > \frac{ {( {y}^{2} )}^{2} - { ({3}^{2} )}^{2} }{y - 3} \\ \\ = > \frac{( {y}^{2} - {3}^{2} ) \: ( {y}^{2} + {3}^{2} )}{y - 3} \\ \\ = > \frac{(y - 3)(y + 3)( {y}^{2} + {3}^{2} )}{y - 3} \\ \\ = > (y + 3)( {y}^{2} + {3}^{2} )$

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