divide2x^3+3x^2+4x+10 by x^2+x+1 and verify that dividend = Quotient×divisor+Reminder
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Answer :
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Step-by-step explanation:
We know that the division algorithm states that:
We know that the division algorithm states that: Dividend=(Divisor×quotient)+Remainder
We know that the division algorithm states that: Dividend=(Divisor×quotient)+RemainderHere it is given that the dividend is p(x)=4x
We know that the division algorithm states that: Dividend=(Divisor×quotient)+RemainderHere it is given that the dividend is p(x)=4x 3+2x 2 −10x+2, the divisor is g(x), the quotient is 2x 2 +4x+1 and the remainder is 5,
therefore,
therefore,4x 3 +2x 2 −10x+2=[g(x)(2x 2 +4x+1)]+5⇒g(x)=2x 2+4x+14x 3 +2x 2 −10x+2
therefore,4x 3 +2x 2 −10x+2=[g(x)(2x 2 +4x+1)]+5⇒g(x)=2x 2+4x+14x 3 +2x 2 −10x+2
therefore,4x 3 +2x 2 −10x+2=[g(x)(2x 2 +4x+1)]+5⇒g(x)=2x 2+4x+14x 3 +2x 2 −10x+2 The division is shown above.
therefore,4x 3 +2x 2 −10x+2=[g(x)(2x 2 +4x+1)]+5⇒g(x)=2x 2+4x+14x 3 +2x 2 −10x+2 The division is shown above.Hence, from the above division, we get that the divisor is g(x)=2x−3