Math, asked by tanmayee123456, 17 hours ago

The width of each of the five continuous classes in a frequency distribution is 5 and the upper-class limit of
the upper class is 60. The lower-class limit of the lowest class is I WANT LOWER LIMIT

Answers

Answered by rayhansaifi011
3

Step-by-step explanation:

Let x and y be the upper and lower class limit of frequency distribution.

⇒ width of the class = 5

⇒ x−y=5 ---- ( 1 )

⇒ Also, given lower class y=10. On putting y=10 in Eq.( 1 ), we get,

⇒ x=15

⇒ So, the upper class limit of the lowest class is 15.

⇒Hence, the upper class limit of the highest class=(Number of continuous classes x Class width + Lower class limit of the lowest class)

⇒ The upper class limit of the highest class = 5×5+10=25+10=35

∴ The upper class limit of the highest class is 35.

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Answered by snandini061
3

Answer:

your answer is in above attachment

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