Question

divided 200 into two parts such that 1/3 red of the first and 1/2 of the second are equal .

Answer 1

Define x:

Let one part be x.

The other part = 200 - x

Equation:

1/3 of the first is equal to 1/2 of the second

1/3 x = 1/2 ( 200 - x)

Solve x:

1/3 x = 1/2 ( 200 - x)

1/3 x = 100 - 1/2 x

1/3 x + 1/2 x = 100

5/6 x = 100

x = 100 ÷ 5/6

x = 120

Find the parts:

first part = x = 120

second part = 200 - x = 200 - 120 = 80

Answer: The two parts are 120 and 80

Answer 2

HELLO FRIEND HERE IS YOUR ANSWER,,,,,

We have to find the two containing parts,,

In the first part we have been given that $\frac{1}{3}$ will be the first part equal to $\frac{1}{2}$ as the second part.

One part should be a variable , so let the part the named as "y"

First part will be = y

Second part will be = 200 - y

Since, second part will be a difference between the first one.

Therefore,,,

$= > \frac{1}{3} y = \frac{1}{2} (200 - y)$


$= > \frac{1}{3} y = \frac{200}{2} - \frac{1}{2} y \\ \\ \\ = > \frac{1}{3} y = 100 - \frac{1}{2} y \\ \\ \\ = > \frac{1}{3} y + \frac{1}{2} y = 100 \\ \\ \\ = > \frac{5}{6} y = 100$

Therefore,,, by simplifying,,,

$= > \: \: y \: = \frac{100}{ \frac{5}{6} } \\ \\ \\ = > \: \: y \: = \frac{600}{5} \\ \\ \\ = > \: \: y \: = 120$

Substituting into given variables we get,,,,

$First \: \: Part \: \: Will \: \: be \: = y = 120 \\ \\ \\ Second \: \: Part \: \: Will \: \: be \: \: = 200 - y = 200 - 120 \\ Second \: \: Part = 80$

Final solution gives us the two parts as, $\textbf{120}$ and $\textbf{80}$

Which are the required solutions for this type of query.

HOPE IT HELPS YOU AND CLEARS THE DOUBTS FOR FRACTIONALLY OBTAINING THE VALUES!!!!!!