divided the following monomial by the given monomial (1) 6x^3y^2z^2 by 3x^2z
(2) -72a^4b^5c^8 by -9a^2b^2c^2
Answers
Answer:
SORRY I DONT KNOW THE ANSWER BUT THIS MIGHT HELP YOU
Step-by-step explanation:
Factors:
In a product of two or more expressions each expression is called a factor of the product.
Factorization:
The process of writing a given expression as a product of two or more factors is called factorization.
Division of a monomial by monomial:
To divide one monomial by another divide the numerical coefficient of the dividend by the numerical coefficient of the divisor and the powers of variables in the dividend by the corresponding powers in the divisor then multiply all the quotients.
Division of a polynomial by a monomial:
To divide a polynomial by a monomial divide each term of the polynomial by the monomial and then add all the partial quotients thus obtained.
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Solution:
1)
(5x² – 6x) ÷ 3x
=[x(5x-6)] / 3x
Cancelling x
=(5x-6)/3
2)
(3y^8– 4y^6 + 5y⁴) ÷ y⁴
= y⁴(3y⁴ -4y² +5)/ y⁴
=3y⁴-4y²+5
3)
8(x³y²z² + x²y³z² + x²y²z³) ÷ 4x²y²z²
=8x² y²z²(x+y+z)/ 4x²y²z²
= 2(x+y+z)
4)
(x³ + 2x² + 3x) ÷ 2x
=x(x² +2x+3)/2x
=( x² +2x+3)/2
5)
(p³q^6 – p^6q³) ÷ p³q³
= p³ q³(q³- p³) / p³q³
=(q³ - p³)
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Hope this will help you....