Question

factorise the expression x y z(z square + 6 z- 16) divided 2 Y (Z - 2)​

Answer 1

4yz(z

2

+6z−16)÷2y(z+8)

2y(z+8)

4yz(z

2

+8z−2z−16)

z+8

2z(z(z+8)−2(z+8))

⇒

(z+8)

2z[(z+8)(z−2)]

2z(z−2)=2z

2

−4z.

Answer 2

Answer:

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Step-by-step explanation:

= xyz ( z^2 + 6z - 16 )

2y ( z - 2 )

= ( z^2 + 8z - 2z - 16 )

2y ( z - 2 )

= xyz [ z ( z + 8 ) - 2 ( z + 8 ) ]

2y ( z - 2 )

= xyz ( z - 2 ) ( z + 8 )

2y ( z - 2 )

= xyz ( z + 8 )

2y

= x × y × z ( z + 8 )

2 × y

= xy ( z + 8 )

2