Question

dividing 2x cube + 6X square + X + 5 by (X + 3) the remainder is​

Answer 1

Answer:

check out my slon please

Answer 2

$Let \: p(x) = 2x^{3} + 6x^{2} + x + 5 \: and \\g(x) = (x+3)$

$If \: p(x) \: is \: divided \: by \: g(x) \: then \: the \\remainder \: is \: p(-3)$

$p(-3) = 2(-3)^{3} + 6(-3)^{2} + (-3) + 5 \\= 2 \times (-27) + 6 \times 9 - 3 + 5 \\= -54 + 54 - 3 + 5 \\= -3 + 5 \\= 2$

Therefore.,

$\red{ Required \: remainder } \green { = 2 }$

$Option \: \green { ( a ) } \: is \: correct.$

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