Question

Division method by Reminder theorem 3x²+4x+1 by x+1

Answer 1

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Answer 2

By remainder Theorem ;
Here dividend=3x2+4x+1 and divisior= x+1

=) Put divisior =0
= x+1=0
=x= (-1)

=)Let p(x)= 3x2+4x+1

put x=(-1) in p(x) we get ,

p(-1) =3(-1)2+4(-1)

=)3 -4+1

=) -1+1

=)0


Thus, remainder is 0.


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