if -5 is a root of the quadratic equation 2x^2 + px - 15 ,find the value of p
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Answered by
2
2(-5)^2+p(-5)-15=0
50-p5-15=0
35-p5=0
P5=35
P=35/5
P=7
50-p5-15=0
35-p5=0
P5=35
P=35/5
P=7
Answered by
1
Hey!!!!
We have x = - 5 , a root of 2x² + px - 15
Thus , 2(-5)² + p(-5) - 15 = 0
=> 2(25) - 5p - 15 = 0
=> 5( 10 - p - 3 ) = 0
=> p = 7
Hope this helps
We have x = - 5 , a root of 2x² + px - 15
Thus , 2(-5)² + p(-5) - 15 = 0
=> 2(25) - 5p - 15 = 0
=> 5( 10 - p - 3 ) = 0
=> p = 7
Hope this helps
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