Question

divisor = x - 2;
remainder = 0;
quotient = x2 + 2x +3;
dividend = 2​

Answer 1

Answer:

What is the question? I mean what do we have to find out?

Answer 2

$dividend = divisor \times quotient + remainder$

$2 = (x - 2)( {x}^{2} + 2x + 3) + 0$

$2 = {x}^{3} + 2 {x}^{2} + 3x - 2 {x}^{2} - 4x - 6$

${ x}^{3} - x - 6 = 2$

${x}^{3} - x = 2 + 6$

${ x}^{3} - x = 8$

$x( {x}^{2} - 1) = 8$

$from \: this \: we \: get \: 2 \: values \: of \: x$

$x = 8$

${x}^{2} = 8 + 1$

${x}^{2} = 9$

$x = \sqrt{9}$

$x = + 1 \: or \: - 1$