Math, asked by lokeshsharma5830, 1 year ago

diwakar can do work in 17/2 days after diwakar worked for 2 day bhaskar joined them they worked for one day the capacity of of Bhaskar is double the capacity of diwakar on the 4 day work is completed by both the help of Harsha how many day required by Harsha to do the work alone

Answers

Answered by amitnrw
3

Answer:

17 days required by Harsha to do the same work alone

Step-by-step explanation:

Diwakar can do work in 17/2 days

=> Diawakar 1 Day work  = 2/17  

the capacity of of Bhaskar is double the capacity of diwakar

=> Bhaskar 1 day work  = 4/17

Let say Harsha can complete Work alone in H days

then Harsha 1 day Work = 1/H

Diwakar Worked for 4 Days  

Bhaskar worked for  2 days

Harsha Worked for   1 Days

Total Work Done =  4 * (2/17) + 2(4/17)  + 1/H   =  1

=> 8H  + 8H  + 17 = 17H

=> 17 = H

=> H = 17

17 days required by Harsha to do the same work alone

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