Question

do 6th number......... ....​

Answer 1

Answer:

Here's your answer dude..

Answer 2

$\blue{\bold{\underline{\underline{\boxed{answer}}}}} \: \\ (x \times y) ^{ - 1} =( \frac{ - 2}{3} \times \frac{ - 3}{4} ) ^{ - 1} \\ = ( \frac{1}{2} )^{ - 1} = \boxed{2} \\ x^{ - 1} \times y ^{ - 1} = ( \frac{ - 2}{3} )^{ - 1} \times ( \frac{ - 3}{4} ) ^{ - 1} \\ = ( \frac{1}{2}) ^{ - 1} = \boxed{2} \\ therefore \: (x \times y) ^{ - 1} = x ^{ - 1} \times y ^{ - 1} \\ i \: hope \: this \: help \: you \: \\ mark \: it \: as \: brainliest .\:$