Question

do 8,6 and 11from Pythagoras triplet​

Answer 1

Used Formula :-

♣️ Pythagoras triplet :

$\bigstar \: \color{magenta}\boxed{ \bf Hypotenuse ^{2} = Base^{2} + Height^{2} } \: \color{black} \bigstar$

We can also write,

$\bigstar \color{magenta} \: \boxed{ \bf {a}^{2} + {b}^{2} = {c}^{2} } \: \color{black}\bigstar$

$\:$

Solution :-

Given :

Sides of a right triange are :

• 8 (Height)
• 6 (Base)
• 11 (Hypotenuse)

According to the question by using formula we get,

$\implies \: \bf Hypotenuse ^{2} = Base^{2} + Height^{2}$

$\implies \: \sf 11 ^{2} \: = \: 8^{2} \: + \: 6^{2}$

$\implies \: \sf 121 \: = \: 64 \: + \: 36$

$\implies \: \sf 121 \: ≠ \: 100$

$\implies \: \bf \red{ L.H.S \: ≠ \: R.H.S}$

∴ Hence, it is not a right angled triange.

$\:$

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Answer 2

Answer:

Pythagoras triplet formula :

$\color{blue}\boxed{ \bf Hypotenuse ^{2} = Base^{2} + Height^{2} }$

$\color{red}\boxed{ \sf \:Answer :-}$

$\bf \ \bigstar \: Height \implies8$

$\bf \ \bigstar \: Base\implies6$

$\bf \ \bigstar \: Hypotenuse\implies11$

• By using the formula we will get:

$\: \bf \orange {\maltese \: Hypotenuse ^{2} = Base^{2} + Height^{2}}$

That means:

$\rightarrow \: \rm 11 ^{2} \: = \: 8^{2} \: + \: 6^{2}$

$\rightarrow \: \rm 121 \: = \: 64 \: + \: 36$

• 11²=121
• 8²=64
• 6²=36

$\rightarrow\: \rm 121 \: ≠ \: 100$

$\: \rm { L.H.S \: \red≠ \: R.H.S}$

☞, So,it is not a right angled triangle.

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