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SOLUTION OF QUESTION NO. 6
in triangle ABC,DE||BC
Then according to Thels therom
AD/DB = AE/EC
X/X-2 = X+2/X-1
X×(X-1) = (X+2)×(X-2)
X^2-X = X^2-2^2
X^2-X = X^2-4
X^2-X^2=X-4
0 = X-4
4 =X
The value of X is equal to 4.
in triangle ABC,DE||BC
Then according to Thels therom
AD/DB = AE/EC
X/X-2 = X+2/X-1
X×(X-1) = (X+2)×(X-2)
X^2-X = X^2-2^2
X^2-X = X^2-4
X^2-X^2=X-4
0 = X-4
4 =X
The value of X is equal to 4.
harshvardhan3:
can u sure this answer
ya........of course
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