Math, asked by Payalkajal, 1 year ago

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shadowsabers03: Square of side 4 unit.

Answers

Answered by shadowsabers03
2

You can choose any of the following.

1. Square of side 4 unit.

Perimeter = 4a = 4 × 4 = 16 unit²

Area = a² = 4² = 16 unit²

2. Circle of radius 2 unit.

Perimeter = 2πr = 2π × 2 = 4π unit²

Area = πr² = π × 2² = 4π unit²

3. An equilateral triangle of side 4√3 unit.

Perimeter = 3a = 3 × 4√3 = 12√3 unit²

Area = (a²√3) / 4 = ((4√3)² √3) / 4 = 48√3 / 4 =  12√3 unit²

4. A regular hexagon of side  4/√3  unit.

Perimeter = 6a = 6 × 4/√3 = 24/√3 = 8√3

Area = (6√3 a²)/4 = (6√3 × (4/√3)²)/4 = (6√3 × 16 / 3)/4 = 32√3 / 4 = 8√3 unit²

5. A rhombus which satisfies the following property (But it's not at all easy):

The sum of reciprocals of squares of diagonals should be 1/16.

I.e.,

\boxed{\sf{\frac{1}{(d_1)^2}+\frac{1}{(d_2)^2}=\frac{1}{16}}}

For the diagonals of the rhombus  d₁  and  d₂ .

Hope these may be helpful.

If you're studying in lower class, then it should be better to choose the first one.

Ask me if you have any doubts in my answer.

Please mark it as the brainliest.

             

Thank you. :-))

             

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