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1. a) P (spinning of wheel) = number of outcomes / Total number of outcomes
p (E) = 1 / 5
1. b) P (tossing two coins together) = 2 / 4
= 1 / 2
Therefore, P (E) = 1 / 2 = 0.5
Therefore, outcomes of this experiment is 1 / 2.
2. a) P (getting a prime number) = No. of trails/ Total no. of trails
P (E) = 3 / 6 = 1 / 2
P (E) = 1/2
2. b) = P (E) + P (F) = 1 (100%)
0.5 + P (F) = 1
P (F) = 1 - 0.5
P (F) = 0.5
Therefore, the outcomes of not getting a prime number is 0.5 (or) 1/2
2. c) P (E) = No. of outcomes / Total no. of outcomes
P (E) = 1 / 6
Therefore, the outcomes of gettting a number which is more than 5 is 1 / 6.
2. d) P (E) + P (F) = 1
1 / 6 + P (F) = 1
P (F) = 1 - 1/6
P (F) = 5 / 6
Therefore, the number of outcomes of a number which is not greater than 5 are 5 / 6.
3. a) P (E) = No. of outcomes / Total number of outcomes
P (E) = 1 / 5
Therefore, the probability of getting the pointer to be stopped at D is 1 / 5.
3. b) P (E) = No. of Ace in a deck of cards / Total no. of cards in a deck of cards
P (E) = 4 / 52
P (E) = 1 / 13.
Therefore, the probability of getting Ace is 1 / 13.
3. c) P (E) = Total no. of red apples / Total no. of apples
P (E) = 4 / 7
Therefore, the provability of getting a red apple is 4 / 7.
Thanks.
p (E) = 1 / 5
1. b) P (tossing two coins together) = 2 / 4
= 1 / 2
Therefore, P (E) = 1 / 2 = 0.5
Therefore, outcomes of this experiment is 1 / 2.
2. a) P (getting a prime number) = No. of trails/ Total no. of trails
P (E) = 3 / 6 = 1 / 2
P (E) = 1/2
2. b) = P (E) + P (F) = 1 (100%)
0.5 + P (F) = 1
P (F) = 1 - 0.5
P (F) = 0.5
Therefore, the outcomes of not getting a prime number is 0.5 (or) 1/2
2. c) P (E) = No. of outcomes / Total no. of outcomes
P (E) = 1 / 6
Therefore, the outcomes of gettting a number which is more than 5 is 1 / 6.
2. d) P (E) + P (F) = 1
1 / 6 + P (F) = 1
P (F) = 1 - 1/6
P (F) = 5 / 6
Therefore, the number of outcomes of a number which is not greater than 5 are 5 / 6.
3. a) P (E) = No. of outcomes / Total number of outcomes
P (E) = 1 / 5
Therefore, the probability of getting the pointer to be stopped at D is 1 / 5.
3. b) P (E) = No. of Ace in a deck of cards / Total no. of cards in a deck of cards
P (E) = 4 / 52
P (E) = 1 / 13.
Therefore, the probability of getting Ace is 1 / 13.
3. c) P (E) = Total no. of red apples / Total no. of apples
P (E) = 4 / 7
Therefore, the provability of getting a red apple is 4 / 7.
Thanks.
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