Math, asked by anujgargsp925dq, 11 months ago

fast
class 10
chapter 8or 9
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Answered by adityakumar5155

First ,

l=sec+tan

By taking RHS,

(l²+1)/2l

={sec+tan}²+1/{2(sec+tan)}

={sec+tan}²+(sec²-tan²)/{2(sec+tan)}

={sec+tan}²+(sec-tan)(sec+tan)/{2(sec+tan)}

By taking sec+tan common,we get

sec+tan[(sec+tan)+(sec-tan)]/2(sec+tan)

(sec+tan)+(sec-tan)/2 (by canceling sec+tan)

2sec/2

=sec=LHS

adityakumar5155: Sorry for late , this was a little long

anujgargsp925dq: no prob

anujgargsp925dq: keep on answering

adityakumar5155: Accept my friend request

adityakumar5155: and dont forgot to give a thanks

anujgargsp925dq: bro

anujgargsp925dq: how at last u take 2 sec / 2

anujgargsp925dq: by canceling u get sec-tan/2

adityakumar5155: see it carefully i have canceled sec+tan which was taken as common(outside the bracket) , inner one couldn't be canceled

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