Question

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Answer 1

Let radius of first circle = 2x

and radius of another circle = 3x

Now,

$Circumference \: of \: {1}^{st} 【C1】 = 2\pi \times 2x \\ = 4\pi x.........(1) \\ and \\ circumference \: of \: {2}^{nd} 【C2】 = 2\pi \times 3x \\ = 6\pi x ........(2) \\ \\ (2) \div (1) \\ \frac{C1}{C2} = \frac{4\pi x}{6\pi x} = \frac{2}{3}$

Therefore, the ratio of their circumference = 2:3