Math, asked by mysticd, 1 year ago

do it fast with explaination

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Answered by Anurag19
1

Area of equilateral triangle is √3

⇒ √3 a²/4 = √3

⇒ a² = 4

⇒ a = 2

 For any Equilateral Triangle

The radius of Incircle = (Side/ 2√3)
                                  = 2/2
√3 = 1/√3
Circumference = 2 \pi r
                         = 2 \pi 1/√3
                         = 2/√3 ×  \pi



Anurag19: mark it as brainliest
mysticd: check it again.
mysticd: we don't have that answer
mysticd: a)pi/root3 b)pi* root 3c)2*pi /root3 d)2*pi*root3
abhi178: answrr is 2π/√3
Answered by abhi178
0
area of an equilateral ∆ = √3 m²
√3/4 × (side length) ² = √3

side length = 2 m

now,

, radius of circle divide the triangle into 3 parts .

area of sum of three pàrts = area of ∆
1/2 × r × L + 1/2 × r × L + 1/2 × r × L = √3

3/2 × ( r ) × L = √3

3/2 × r × 2 = √3

r = 1/√3

so, radius of circle = 1/√3 m

circumstance = 2πr = 2π/√3 m

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