do it fast with explaination
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any function is continuous function at a point x = a only when ,
f( a- ) = f(a + ) = f(a )
here ,
f(x ) = x² -( A +2)x + A when x ≠ 2
lim (x → 2-) { x² -(A +2)x + A }
put x = 2 , we see no any format gain by this , give finite value ,
e.g
f(2-) = 4 -(A +2)2 + A = 4 - 2A - 4 + A = -A
again,
similarly,
lim( x → 2+) { x² -(A +2)x + A}
f(2+) = 4 -(A +2)2 + A = - A
so,
f(2-)= f (2+) = f(2)
-A = - A = 2
A = -2
f( a- ) = f(a + ) = f(a )
here ,
f(x ) = x² -( A +2)x + A when x ≠ 2
lim (x → 2-) { x² -(A +2)x + A }
put x = 2 , we see no any format gain by this , give finite value ,
e.g
f(2-) = 4 -(A +2)2 + A = 4 - 2A - 4 + A = -A
again,
similarly,
lim( x → 2+) { x² -(A +2)x + A}
f(2+) = 4 -(A +2)2 + A = - A
so,
f(2-)= f (2+) = f(2)
-A = - A = 2
A = -2
abhi178:
sir , i think option have mistake
Answered by
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Answer:
lim( x → 2+) { x² -(A +2)x + A}
f(2+) = 4 -(A +2)2 + A = - A
f(2-)= f (2+) = f(2)
A = -2
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