Question

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Answer 1

Answer:-

$\sf{perimter\:of\:paper=17\dfrac{11}{15}\;\;cm}$

Given:-

• Length of rectangular paper = $\sf{5\dfrac{2}{3}\;\;cm}$
• Breadth of rectangular paper = $\sf{3\dfrac{1}{5}\;\;cm}$

To find:-

Perimeter of rectangular paper =?

Formula required:-

• Formula to calculate perimeter of rectangle
• $\boxed{\sf{Perimeter\:of\:rectangle=2\times ( length + breadth)}}$

Calculation:-

• Converting length and breadth given in mixed fraction into improper fraction

$\implies\sf{length=5\dfrac{2}{3}\;\;cm}$

$\implies\sf{length=\dfrac{17}{3}\;\;cm}$

and

$\implies\sf{breadth=3\dfrac{1}{5}\;\;cm}$

$\implies\sf{breadth=\dfrac{16}{5}\;\;cm}$

• Calculating perimeter of rectangular paper
• Using formula for perimeter of rectangle

$\longrightarrow\sf{perimeter\:of\:paper=2\times (length + breadth)}$

$\longrightarrow\sf{perimeter\:of\:paper=2\times \bigg(\dfrac{17}{3} + \dfrac{16}{5}\bigg)}$

$\longrightarrow\sf{perimeter\:of\:paper=2\times \bigg(\dfrac{17(5)+16(3)}{15}\bigg)}$

$\longrightarrow\sf{perimeter\:of\:paper=2\times \bigg(\dfrac{85+48}{15}\bigg)}$

$\longrightarrow\sf{perimeter\:of\:paper=2\times \bigg(\dfrac{133}{15}\bigg)}$

$\longrightarrow\boxed{\boxed{\sf{perimeter\:of\:paper=\dfrac{266}{15}\;\;cm=17\dfrac{11}{15}\;\;cm}}}$

Answer 2

Answer:

Answer:

Length of rectangular Paper = 5 2/3 = 17/3 cm

and,

Breadth of rectangular Paper = 3 1/5 = 16/5 cm

Therefore,

Perimeter of rectangular Paper = 2 ( L + B )

 => 2 ( 17/3 + 16/5 ) cm

=> 2 ( (17 × 5) + (16 × 3) / 15 ) cm

=> 2 ( 85 + 48/15 ) cm

=> 2 133/15 cm

hope this helps you