Question

Do it, if you want...........​

Answer 1

Look at the attachment : -

: - Ans = 50.4

Hop its helpful

Answer 2

reaction between carbon and oxygen is

C plus O2 is equal to co2.

hair Big C that one mole of carbon reacts with one mole of oxygen to form 1 mole of CO2.

we know mass of C is equal to 12 gram per mole.

molar mass of O2 is equal to 32 gram per mole.

and Maar mass of seo2 is equal to 44 gram per mole.

so we can also say that 12 gram of carbon reacts with 32 gram of oxygen to form 44 gram of CO2.

or 27 gram of carbon reacts with(32/12)×27= 72 gram but oxygen is given 8 gram( excess amount of oxygen)

show carbon is limiting reagent.

now one mole of carbon forms one mole of CO2

aur 12 gram of C form 44 gram of CO2

aur 27 gram of C form 44 by 12 into 27 is equal to 99 gram of co2.

so number of mole of seo2 is equal to 99 gram by 44 gram mole is equal to 9 by 4

volume of seo2 is equal to 22.4 into 9 by 4 is equal to 50.4 L.

hymns volume of seo2 gas produced at ntp is 50.4 L

also mass of unreacted O2 is equal to 88 gram - 22 gram is equal to 16 gram

the number of mole of Oxygen and reacted is equal to 16 gram by 32 gram mole is equal to 0.5 mole

hymns volume of unreacted oxygen is equal to 22.4×0.5=11.2L