Question

do it plzzzzzz.... ......​

Answer 1

Diagram:-

$\setlength{\unitlength}{1.2 cm}\begin{picture}(0,0)\linethickness{0.5mm}\qbezier(0,0)(0,0)(1,3)\qbezier(5,0)(5,0)(4,3)\qbezier(1,3)(1,3)(4,3)\qbezier(3,0)(8.2,0)(0,0)\put(-0.5,-0.3){ \sf A }\put(5.3,-0.3){ \sf B }\put(4.2,3.1){ \sf C }\put(0.6,3.1){ \sf D }\end{picture}$

Height of a trapezium=14cm

Let :—

the shorter parallel side=x

The larger parallel side=x+16

As we know that in a Trapezium

${\boxed{\sf Area={\dfrac {1}{2}}\times (sum\:of\:parallel\:sides)×height}}$

Substitute the values:-

$\qquad\quad {:}\longmapsto\sf {\dfrac {1}{2}}(x+x+16)×14=112$

$\qquad\quad {:}\longmapsto\sf {\dfrac {1}{\cancel{2}}}(2x+16)×\cancel {14}=112$

$\qquad\quad {:}\longmapsto\sf 7 (2x+16)=112$

$\qquad\quad {:}\longmapsto\sf (2x+16) 7=112$[/tex]

$\qquad\quad {:}\longmapsto\sf 2x+16=\cancel{{\dfrac {112}{7}}}$

$\qquad\quad {:}\longmapsto\sf 2x+16=16$

$\qquad\quad {:}\longmapsto\sf 2x=16-16$

$\qquad\quad {:}\longmapsto\sf 2x=0$

$\qquad\quad {:}\longmapsto\sf x={\dfrac {1}{2}}$

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Shorter parallel side=${\dfrac {1}{2}}=0.5cm$

Larger parallel side=$16+0.5=16.5cm$

Answer 2

Answer:

182=1/2*14(x+x+16)

182=1/2*14(2x+16)

182=2×1/14=2x+16

26=2x+16

26-16=2x

10=2x

x=10/2

x=5

the base of parallelogram is 5+16=21

hope it helps you☺️