do it with complete explanation
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See, qpo is a triangle. Now, angle qps=40 and pqt=30.
Therefore angle (pqt+qps+poq) =180(angle sum property of triangle)
Angle poq=110.(simple substraction)
Poq+qor=180(linear pair)
Qor=70
=>tor=70.
Now join tu.
Tor=2tur(angle at the centre is double the angle subtended at any point on the circumference)
Tur=1/2 tor=70 /2=35
[Note, this thereom is very important and applicable here.
If u see it care fully u will notice that minor arc tr is same for both case, I. E, for angle tor and tur. Therefore this theorem is used.]
Hope this clears ur doubt. Please check the calculation.
Therefore angle (pqt+qps+poq) =180(angle sum property of triangle)
Angle poq=110.(simple substraction)
Poq+qor=180(linear pair)
Qor=70
=>tor=70.
Now join tu.
Tor=2tur(angle at the centre is double the angle subtended at any point on the circumference)
Tur=1/2 tor=70 /2=35
[Note, this thereom is very important and applicable here.
If u see it care fully u will notice that minor arc tr is same for both case, I. E, for angle tor and tur. Therefore this theorem is used.]
Hope this clears ur doubt. Please check the calculation.
Shreya01:
I remember to add this point.. since pr is diameter. Therefore it passess through centre.
I forget to add this point.. plz add it
Answered by
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Answer:
See, qpo is a triangle. Now, angle qps=40 and pqt=30.
Now angle (pqt+qps+poq) =180(angle sum property of triangle) Angle poq=110.(simple substraction) Poq and Qor=180(linear pair) Qor=70
=>tor=70. So join tu.
Tor=2tur(angle at the centre is double the angle subtended at any point on the circumference)
Tur=1/2 tor=70 /2=35
Step-by-step explanation:
Hope it will help
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