Question

do it with correct solution!!​

Answer 1

GIVEN :-

• Dimensions of rectangle are 100 cm × 80 cm

TO FIND :-

• Ratio of length to it's breadth
• Ratio of breadth to its perimeter

SOLUTION :-

• We have Dimensions of rectangle as 100 cm × 80 cm

From this ,

• Length = 100 cm
• Breadth = 80 cm

Perimeter of a rectangle is given by ,

$\large {\underline{\boxed {\bigstar{\red {\sf{ \: p = 2(l + b)}}}}}}$

Where ,

• l is length of rectangle
• b is breadth of rectangle

$\implies \sf \: p = 2(100 + 80) \\ \\ \implies \sf \: p = 2(180) \\ \\ \implies {\underline {\boxed {\blue{\sf {\: p = 360 \: cm}}}}}$

(1) Ratio of length to its breadth

$\sf \:ratio \: of \: length \: to \: its \: breadth \sf \: = 100 : 80 \\ \\ \implies {\underline {\boxed {\blue {\sf{ratio \: of \: length \: to \: its \: breadth = 5 :4}}}}}$

(2) Ratio of breadth to it's perimeter

$\sf \: ratio \: of \: breadth \: to \: its \: perimeter = 80 : 360 \\ \\ \implies {\underline {\boxed {\blue {\sf {\:ratio \: of \: breadth \: to \: its \: perimeter = 2 : 9}}}}}$

∴ The ratio of length to its breadth = 5 : 4

The ratio of breadth to it's perimeter = 2 : 9

ADDITIONAL INFO :-

$\sf \: (1) \: area \: of \: rectangle = length \times breadth \\ \\ \sf (2) \: perimeter \: of \: square = 4(side) \\ \\ \sf (3) \: area \: of \: square = {(side)}^{2} \\ \\ \sf (4) \: perimeter \: of \: triangle = sum \: of measures \: of\: sides \\ \\ \sf( 5)area \: of \: triangle = \frac{1}{2} \times breadth \times height$

Answer 2

$\huge\underline\bold\red{Answer:-}$

$\large\underline\bold\pink{Given:-}$

Dimensions of rectangle = 100 cm × 80 cm

$\large\underline\bold\green{To\:Find:-}$

• Ratio of length to it's breadth

• Ratio of breadth to its perimeter

We have Dimensions of rectangle as 100 cm × 80 cm

From this -

Length = 100 cm

Breadth = 80 cm

Perimeter of a rectangle is :-

$\large {\underline{\boxed {\bigstar{\green {\sf{ \: p = 2(l + b)}}}}}}$

Where :-

• l $\implies$ length

• b $\implies$ breadth

$\implies \sf \: p = 2(100 + 80) \\ \\ \implies \sf \: p = 2(180) \\ \\ \implies {\underline {\boxed {\orange{\sf {\: p = 360 \: cm}}}}}$

(1) Ratio of length to its breadth

$\sf \:ratio \: of \: length \: to \: its \: breadth \sf \: = 100 : 80 \\ \\ \implies {\underline {\boxed {\pink {\sf{ratio \: of \: length \: to \: its \: breadth = 5 :4}}}}}$

Ratio of breadth to it's perimeter :-

$\sf \: ratio \: of \: breadth \: to \: its \: perimeter = 80 : 360 \\ \\ \implies {\underline {\boxed {\blue {\sf {\:ratio \: of \: breadth \: to \: its \: perimeter = 2 : 9}}}}}$

∴ The ratio of length to its breadth = 5 : 4

The ratio of breadth to it's perimeter $\dashrightarrow$ 2 : 9