Question

do it with explanation​

Answer 1

Answer:-

• $\underline{\boxed{\red{\large{\rm{Distance = 1.65 \: km}}}}}$

Given,

• Time taken = 5 secs
• Speed = 330 ms⁻¹

To find :-

• The distance between Shreya and the point from where the lightning occurs.

Solution :-

• Let us consider the distance be 'x' m.

We know that,

$\longrightarrow \bf Speed = \dfrac{Distance}{Time}$

$\longrightarrow \tt Distance = Speed \times Time$

$\longrightarrow \tt Distance = 330 \: ms^{-1} \times 5 s$

$\longrightarrow \tt Distance = 1650 \: m$

Converting m to km,

$\longrightarrow \boxed{\bf Distance = 1. 65 \: km}$

• Hence, the distance between Shreya and the point from where the lightning occurred is 1.65 km

Answer 2

Refer to the attachment......and try a question few times by yourself before asking.