do long division of -5z^6+6z4+z^2+4 divide with 2x^2
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Answer:
quotient =-2z⁴+3z²
remainder=-z⁶+z²+4
Step-by-step explanation:
2z²)-5z⁶+6z⁴+z²+4(-2z⁴+3z²
+4z⁶
-z⁶+6z⁴+z²+4
-6z⁴
-z⁶ +z²+4
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