Question

do not say pic isn't clear​

Answer 1

Answer:

Hope this helps you mate

Answer 2

In the circuit shown in the figure. the input voltage V1 is 20 V, Vbe - and Vce - 0 The values of 1g 1c and beta are given by

V i =V

BE+R

BiB ---------(1)

20=500×10

3×iB

iB =40μA

V o =V CE −RCiC ------------(2)

20=4×10

3iC

iC=5mA

β= IB

IC = 40μA

5mA =125

hope it helps u....!!