Question

do only last question

Answer 1

IN TRIANGLE ABC AND TRIANGLE EDC

AB = DE [GIVEN]

ANGLE C = ANGLE C [COMMON]

AND BC = DC GIVEN

THEREFORE TRIANGLE ABC CONGRUENT TO TRIANGLE EDC BY SAS CONGRUENCY RULE

Answer 2

consider ∆abc and ∆edc,we get
ab=de(given)
bc=dc(given
angle c =angle c
by SSA
∆abc≈∆edc