do question no. 2 pls fast
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Hey there,
If a,b and c are in AP then
2b=a+c
Similarly
2k+1, 6 and 3k+1 are in AP
So we get,
12=5k+2
5k=10
Therefore k=2
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
Regards
07161020
Ace
If a,b and c are in AP then
2b=a+c
Similarly
2k+1, 6 and 3k+1 are in AP
So we get,
12=5k+2
5k=10
Therefore k=2
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
Regards
07161020
Ace
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