Question

Factorise

p2-4pq+4q2-r2

Answer 1

Given us

p² - 4pq + 4q² - r²
= { p² - 2.p.2q + ( 2q )² } - r²
= ( p - 2q )² - r²
= ( p - 2q - r ) ( p - 2q + r )
______________________________
formula used : ↓
a)→ ( a - b )² = a² - 2ab + b²
b) → a² - b² = ( a + b ) ( a - b )
_______________________________
thanks!

Answer 2

Answer:

p

2

−4pq+4q

2

−r

2

=(p)

2

−2×p×2q+(2q)

2

−r

2

[∵(a−b)

2

=a

2

−2ab+b

2

]

=(p−2q)

2

−(r)

2

=(p−2q+r)(p−2q−r)[∵a

2

−b

2

=(a+b)(a−b)]