Question

do sankhya ka laghutm sampwarty aur mahtam sampwartak ya gudan fal 56133 hai. agr inme s ek sankhya ka 1/7, 27 hai , toh dusri sankhya ka 1/3 gyat kre?​

Answer 1

Answer:

know that.. product of two numbers = HCFx LCM. Therefore XY= 12 x 72= 864….(1) According to given condition, their sum is 60 Therefore x+y = 60……….(2) We know that (x-y)² =(x+y)² -4xy Substitute values from 1 & 2 (X-y)² = 3600–4x864=144 X-Y =√144= 12…(3) By solving 2 and 3 We get x=36 and y=24.

Answer 2

Step-by-step explanation:

Let the two numbers be x and y. We know that.. product of two numbers = HCFx LCM. Therefore XY= 12 x 72= 864....(1) According to given condition, their sum is 60 Therefore x+y = 60.. (2) We know that (x-y)² =(x+y)² -4xy Substitute values from 1 & 2 (X-y)² = 3600-4x864-144 X-Y =√144= 12...(3) By solving 2 and 3 We get x-36 and y=24.