Question

1. Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions. In case there is a unique solution, find it by using cross multiplication method.
(v) 2x+3y=6
4x+6y=12
(vi)x-2y=6
3x-6y=0
(viii) 2x + y - 15 = 0
3x-y-5=0 ​

Answer 1

Answer:

Mark me branliest please

Answer 2

Answer:

v) It has Infinitely Many solution

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vi) Has no solution

• x-2y=6
• 3x-6y=0

By substituting method :

x = 6 + 2y (From eqation 1)

Substituting x in equation 2,

3(6+ 2y ) -6y = 0

18 + 6y - 6y = 0

=> 18 ≠ 0

Thus this set of linear equation has no solution

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viii) Has Unique solution

• 2x + y - 15 = 0
• 3x-y-5=0

Adding equation 1 and 2

=> 2x + y - 15 + 3x-y-5 = 0+ 0

=> 5x - 20 = 0

=> x = 20/5

=> x = 4

Substituting x = 4 in equation 1

=> 2(4) + y -15 =0

=> 8 + y - 15 = 0

=> y = 15 - 8

=> y = 7

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Note: Sorry I forgot multiplication method

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