Do this please i am in a deep dicth .
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HI! CHILLAX
REFER TO FIG BELOW
IN ΔABC
AB=AC
⇒∠1=∠2
∠1+∠2=86° (Exterior angle property)
2∠2=86° (∠1=∠2)
∠2=43°
ALSO, ∠P+∠2=180° (LINEAR PAIR)
∠P=180-43=137°
SOLVED!!:)
u can also find P by applying exterior angle property(∠A+∠1=∠P)
though u will have find ∠A first by applying angle sum property.
SUIT URSELF
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