Physics, asked by pasaladinesh765, 4 months ago

doctor advised to use the power of corrected lens is +1.5D then what is the defect of vision ​

Answers

Answered by srutidk2005
4

Explanation:

A lens having a power +1.5 D will have a focal length of

P =1/f

+1.5 D = 1/f

f = 1/1.5 = 2/3 = + 0.67 m.

The focal length is + 0.67m.

The nature of lens is converging type or convex lens.

The defect of the eye is Hyperopia or far-sightedness.

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