does 4,6,8 forms right angle triangle
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Yes
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Let's use phythogorean theorem
Let 8 be C the hypotenuse
Let 4 be the arm A
Let 6 be the arm B
(A)^2 + (B)^2 = (C)^2
= (4)^2 + (6)^2 = (8)^2
= 16+36=64
= 52=64
= Hence 52 is not equal to 64
Therefore, 4,6,8 doesn't form a right angled triangle
Let 8 be C the hypotenuse
Let 4 be the arm A
Let 6 be the arm B
(A)^2 + (B)^2 = (C)^2
= (4)^2 + (6)^2 = (8)^2
= 16+36=64
= 52=64
= Hence 52 is not equal to 64
Therefore, 4,6,8 doesn't form a right angled triangle
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