Question

does any real genius know how to do this question please solve this question


if points doesn't satisfy for this question
then answer my previous question
it is same question of more points​

Answer 1

Answer:

Note that in interval [ 0 , π/4] ,

GIF(x) = [x] = 0

and frictional part , {x} = x

Now half part of your question is solved

$\frac{d}{dx} (3x - 2(0) - 3(0)) = \frac{d}{dx} 3x = 3$

Now your question remains

$\int_{0} ^{ \frac{\pi}{4} } 3( \tan {}^{n} ( x) + \tan {}^{n - 2} (x) ) \: dx \\ \\ = \int_{0} ^{ \frac{\pi}{4} } 3\tan {}^{n - 2} ( x) ( \tan {}^{2} (x) + 1 )\: dx \\ \\ = \int_{0} ^{ \frac{\pi}{4} } 3\tan {}^{n - 2} ( x) \sec {}^{2} (x) \: dx \\ \\ put \: \: tan x\: = u \\ \\ = \int_{0} ^{ 1 }3 u^{n - 2} \: du \\ \\ = \frac{3}{n - 1}$