Question

Does anyone find this answer
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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

let the shortest side=x

hypotenuse = 1-2x

third side =1+x

by the pythagoras theorem

h^2=b^2+p^2

(1-2x)^2=(x)^2+(1+x)^2

1^2+4x^2-4x=x^2+1^2+x^2+2x

1^2+4x^2-4x=2x^2+2x+1

4x^2-2x^2+1-1-4x-2x=0

2x^2-2x=0

2x(x-1)=0

x=1 or x=1/2