does factorising p2 (q - r) - q (r - q) give the result:
(p2 - q) ( r - q ) ?
Answers
Answered by
2
p²(q-r) - q (r-q)
= - p²(r-q) - q(r-q)
= (-p² - q) (r-q)
So, it does not give (p²-q) (r-q)
= - p²(r-q) - q(r-q)
= (-p² - q) (r-q)
So, it does not give (p²-q) (r-q)
Answered by
0
Answer:
No
Step-by-step explanation:
= p2 (q - r) - q (r - q)
= -p2 (r - q) - q (r - q)
= (r - q)(-p2 -q)
Since, the answer is (r - q)(-p2 -q)
Therefore, No
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