Does no variables change in an adiabatic + isothermal system?
Answers
Answered by
0
To maintain the constant temperature energy must leave the system as heat and enter the environment. ... For an adiabatic process, in which no heat flows into or out of the gas because its container is well insulated, Q = 0. If there is also no work done, i.e. a free expansion, there is no change in internal energy.
An isothermal process is a change of a system, in which the temperature remains constant: ΔT = 0. ... In contrast, an adiabatic process is where a systemexchanges no heat with its surroundings (Q = 0).
An isothermal process is a change of a system, in which the temperature remains constant: ΔT = 0. ... In contrast, an adiabatic process is where a systemexchanges no heat with its surroundings (Q = 0).
Answered by
0
An isothermal process is a change of a
system , in which the temperature remains constant: Δ T = 0. This typically occurs when a system is in contact with an outside thermal reservoir ( heat bath), and the change in the system will occur slowly enough to allow the system to continue to adjust to the temperature of the reservoir through heat exchange. In contrast, an
adiabatic process is where a system exchanges no heat with its surroundings ( Q = 0). In other words, in an isothermal process, the value Δ T = 0 and therefore the change in internal energy Δ U = 0 (only for an ideal gas) but Q ≠ 0, while in an adiabatic process, Δ T ≠ 0 but Q = 0.
system , in which the temperature remains constant: Δ T = 0. This typically occurs when a system is in contact with an outside thermal reservoir ( heat bath), and the change in the system will occur slowly enough to allow the system to continue to adjust to the temperature of the reservoir through heat exchange. In contrast, an
adiabatic process is where a system exchanges no heat with its surroundings ( Q = 0). In other words, in an isothermal process, the value Δ T = 0 and therefore the change in internal energy Δ U = 0 (only for an ideal gas) but Q ≠ 0, while in an adiabatic process, Δ T ≠ 0 but Q = 0.
Similar questions