DOES PHOTONS HAVE DE BROGLIE WAVELENGTH?EXPLAIN
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we know that.. photons have rest mass equal to zero but photons carry momentum
=) p = E/C -------------(1)
but we know that energy of photon
=) E = hv -------------( 2 )
here" h" is plank's constant
and 'v ' is frequency of source
by plank's quantum theory..
but we know that momentum is equal to mv
comparing we get de-broglie wavelength.
see attachment...
_____________________________
hope it will. help u
=) p = E/C -------------(1)
but we know that energy of photon
=) E = hv -------------( 2 )
here" h" is plank's constant
and 'v ' is frequency of source
by plank's quantum theory..
but we know that momentum is equal to mv
comparing we get de-broglie wavelength.
see attachment...
_____________________________
hope it will. help u
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Answered by
2
★☆〖Qบęຮτ ı¨ ø nˇ〗☆★
⭐The Dual Nature of Matter⭐
=> de-Broglie's Principle states that "All material particles in motion possess wave characteristics..."
=> de-Broglie's Relationship can be derived by combining the mass and energy relationships proposed by Max Planck, and Albert Einstein...
E = ∫c²dm = Σc²Δm = mc²
E = hν
=> The combination of these two yielded the desired result:
λ = h/mc
=> The above equation is valid for a Photon(γ⁰)
=> The same relation can be extended to every particle of this universe, if the speed of light in vacua(c) is replaced by the ordinary velocity of the particle:
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